Question

suppose a parabola has an axis of symmetry at x=-7, a max ht of 4 and also passes through the point (-6, 0). Write the equation of the parabola in vertex form. HELP! I have several of these to do and I have to show my work. If someone can help me with one, I think I can do the rest myself. PlZ?

Answer 1

this isn't too bad because they give you the vertex of (-7,4)
\[y = a(x-h)^{2} +k\]
(h,k) = (-7,4)
plug in given point (-6,0) for (x,y) then solve for "a"

Answer 2

a=4?? thats what i got.

Answer 3

almost...notice parabola will be opening down since max is given , this implies "a" should be negative right?

Answer 4

gotcha. thanks for the help

Answer 5

yw