Lead(ll) Chloride can be prepared by the reaction of aqueous solutions of lead (ll) nitrate and sodium chloride. The equation is as follows: Pb(NO3)2+2NaCl = PbCl2+2NaNO3
If a solution that contains 49.1 g Pb(NO3)2 is treated with an excess of NaCl...
a) What is the theoretical yield of PbCl2? (41.2 g)
b) If 38.2 g of PbCl2 is obtained, what is percent yield? (92.6%)
I believe answer is in ( ), but need a detailed explanation of how to get it. Thank you so much!

Question

Lead(ll) Chloride can be prepared by the reaction of aqueous solutions of lead (ll) nitrate and sodium chloride.  The equation is as follows:  Pb(NO3)2+2NaCl = PbCl2+2NaNO3
If a solution that contains 49.1 g Pb(NO3)2 is treated with an excess of NaCl...
a) What is the theoretical yield of PbCl2? (41.2 g)
b) If 38.2 g of PbCl2 is obtained, what is percent yield? (92.6%)
 I believe answer is in ( ),  but need a detailed explanation of how to get it. Thank you so much!