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Mathematics 18 Online
OpenStudy (anonymous):

find all the critical points

OpenStudy (amoodarya):

\[f(x)=x \ln(8x) \rightarrow f'=x\frac{ 8 }{ 8x }+\ln(8x) \rightarrow f'=0 \rightarrow \ln(8x)=-1\rightarrow 8x=e^{-1?}\]

OpenStudy (amoodarya):

OpenStudy (anonymous):

i dont understand where you got ln(8x)=-1

OpenStudy (anonymous):

@amoodarya

OpenStudy (loser66):

f' = 1 + ln (8x)\(\rightarrow\) ln(8x)=-1

OpenStudy (anonymous):

for f'(x) i got ln8x+1/8x

OpenStudy (anonymous):

sorry +1/8

OpenStudy (anonymous):

@Loser66

OpenStudy (loser66):

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