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Discrete Math 5 Online
OpenStudy (anonymous):

The following problem refers to strings in A, B, ..., Z. How many four-letter strings are there that begin with A ?

OpenStudy (anonymous):

We have to make 3 choices, right? : the 2nd letter, the 3rd letter and the 4th letter. Each choice is independent, so we multiply them. Number of choices for 2nd letter x Number of choices for 3rd letter x Number of choices for 4th letter How many choices do we have for each letter?

OpenStudy (anonymous):

Hello BangkokGarrett, basically its a total of the 3 choices, they are basically asking the total number of choices

OpenStudy (anonymous):

I understand the question....I'm just trying to get you to fill in the blank. We have 26 choices for each letter. So the number of 4 letter strings that begin with A will be: 26 x 26 x 26

OpenStudy (anonymous):

I'm sorry, for the 3 string its 26^3, so for the 4th string its 26^4? Would that be a safe assumption?

OpenStudy (anonymous):

Its 17576, thk you so much sir

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