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If the complex number x = 3 + bi and |x|2 = 13, which is a possible value of b? A= 2 B= 4 C= 9 D= 10
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take |x|2 = 13 divide both sides by 2, |x|=7.5 7.5 =3 +bi 4.5=bi -4.5i=b or....
|x|=7.5 -7.5 = 3 + bi -10.5=bi +10.5i=b
@ChelsH, do you see how I got this?
I don't fully understand it..
The answer doesn't fit one of the answer choices.
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I get why, |x|=6.5 not 7.5 my bad
|dw:1384301507292:dw|
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