Suppose a ball is thrown straight up into the air, and the height of the ball above the ground is given by the function h(t) = 6 + 37t – 16t2, where h is in feet and t is in seconds. What is the velocity of the ball at time t = 3.2?
(Points : 1)
53 ft/sec
–102.4 ft/sec
–65.4 ft/sec
–32.3 ft/sec
32.4 ft/sec

Question

Suppose a ball is thrown straight up into the air, and the height of the ball above the ground is given by the function h(t) = 6 + 37t – 16t2, where h is in feet and t is in seconds. What is the velocity of the ball at time t = 3.2?
(Points : 1)
       53 ft/sec
       –102.4 ft/sec
       –65.4 ft/sec
       –32.3 ft/sec
       32.4 ft/sec

anonymous · Answer

Suppose a ball is thrown straight up into the air, and the height of the ball above the ground is given by the function h(t) = 6 + 37t – 16t2, where h is in feet and t is in seconds. At what time t does the ball stop going up and start returning to earth?
(Points : 1)
       1.42341 seconds
       0.04684 seconds
       2.46551 seconds
       1.15625 seconds
       4.33232 seconds