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Mathematics 25 Online
OpenStudy (anonymous):

A restaurant offers the following limited lunch menu: Main Courses: Beef, Pork Roast, Duck, Quiche Vegetables: Broccoli, Carrots, Potatoes Beverages: Coffee, Tea, Milk, Soda, Shakes Desserts: Ice Cream, Brownies If one item is selected from each of the four groups, in how many ways can a meal be ordered?

OpenStudy (anonymous):

4 diff items that can be chosen from main course * 3 diff vegetables* 4 beverages* 2 Desserts

OpenStudy (anonymous):

So its 4*4*3*2=96

OpenStudy (anonymous):

Basically use the m*n rule

OpenStudy (anonymous):

I thought it was 4*3*3*2, But thanks!

OpenStudy (anonymous):

Umm why did you think that?

OpenStudy (anonymous):

I was reading it wrong.

OpenStudy (anonymous):

ohhhh :)

OpenStudy (kropot72):

There are 5 choices of beverages.

OpenStudy (anonymous):

Hahahahaha true :) Read it wrong lol

OpenStudy (anonymous):

Need to wear my glasses otherwise the words get smudged together -_-

OpenStudy (anonymous):

I thought so as well! so its 120. 5*4*3*2=120

OpenStudy (anonymous):

Yup :)

OpenStudy (anonymous):

Thanks @kropot72 for pointing that out

OpenStudy (anonymous):

Like wise! Thanks!

OpenStudy (kropot72):

You're welcome :)

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