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find the exact value of cot(13/6), with out using a calculator?
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i am going to guess it is \[\cot(\frac{13\pi}{6})\]
yes sorry . I have the answer in the back of the book as -1.. just not sure how to get there.
first note that \(\frac{13\pi}{6}\) is coterminal with \(\frac{13\pi}{6}-2\pi=\frac{\pi}{6}\)
then find \(\cot(\frac{\pi}{6})=\frac{\cos(\frac{\pi}{6})}{\sin(\frac{\pi}{6})}\)and it is not \(-1\) for sure
ohh I read the back and its sqrt3!
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that makes more sense
\[\frac{\frac{\sqrt3}{2}}{\frac{1}{2}}=\sqrt3\]
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yw
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