Question

what ate the zeroes to the function what are their multiplicants? f(x)=x^4-4x^3+3x^2 @Little_Kay

Answer 1

When you factor out x^2 from the equation you get .. x^2(x^2-4x+3)

Answer 2

x^2(x^2-4x+3)=0 if you replace x with 0 the whole thing becomes 0 so the number 0 is a zero of multiplicity.

Answer 3

of multiplicity 2

Answer 4

the numbers 1 and 3 are zeroes of multiplicity 1

Answer 5

close this one kk

Answer 6

ok got it!

Answer 7

good ( :