* After t hours the distances D1 traveled by car A is given by D1 = 40 t * Car B starts at 10 am and will therefore have spent one hour less than car A when it passes it. After (t - 1) hours, distance D2 traveled by car B is given by D2 = 60 (t-1) * When car B passes car A, they are at the same distance from the starting point and therefore D1 = D2 which gives 40 t = 60 (t-1) *how to solve the above equation for t to find t = 3 hours???

Question

* After t hours the distances D1 traveled by car A is given by   D1 = 40 t   * Car B starts at 10 am and will therefore have spent one hour less than car A when it passes it. After (t - 1) hours, distance D2 traveled by car B is given by   D2 = 60 (t-1)   * When car B passes car A, they are at the same distance from the starting point and therefore D1 = D2 which gives   40 t = 60 (t-1)   *how to solve the above equation for t to find   t = 3 hours???