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Mathematics 22 Online
OpenStudy (anonymous):

solve (0,2pi] cos^2x+2cosx+1=0

OpenStudy (anonymous):

factor the expression.

OpenStudy (anonymous):

?

OpenStudy (anonymous):

(2cosx+1)(cosx-1)

OpenStudy (anonymous):

No, the problem says cos^2x, not 2 cos^2x

OpenStudy (anonymous):

i know :(

OpenStudy (anonymous):

|dw:1384231356203:dw|

OpenStudy (anonymous):

FOIL to see that the factors are correct.

OpenStudy (anonymous):

i will

OpenStudy (anonymous):

|dw:1384231494406:dw|

OpenStudy (anonymous):

right

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

thanks :)

OpenStudy (anonymous):

welcome.

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