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OpenStudy (anonymous):
Rewrite cos5x-cos3x as a product
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OpenStudy (anonymous):
I came up with... -2sin(5theta/3theta/2) sin (5theta-3theta/2) -2sin8theta/2 sin2theta/2 -2sin4theta sintheta
OpenStudy (anonymous):
Can someone verify, thanks.
OpenStudy (ranga):
Use the trigonometric identity: cos(A) - cos(B) = -2sin((A+B)/2)sin((A-B)/2)
OpenStudy (anonymous):
um, thought i had?
OpenStudy (ranga):
And your answer is correct.
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OpenStudy (anonymous):
thanks
OpenStudy (ranga):
You had 5theta/3theta/2 which threw me off.
OpenStudy (ranga):
Welcome.
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