Question

((b-1) (-axb)^(b-2))/(-bax)^(b-1)

Answer 1

Is this the expression?\[\Large \frac{ (b-1)(-axb)^{b-2} }{ (-bax)^{b-1} }\]

Answer 2

yes

Answer 3

You can use the identity:
x^m / x^n = x^(m-n)

Answer 4

ok cool, thanks

Answer 5

you are welcome.

Answer 6

= (b-1) * (-axb)^{ (b-2) - (b - 1) }
= (b-1) * (-axb)^(-1)
= (b-1) / (-axb)
= (1-b) / axb