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Help..?At a certain time of day, a 5.5 foot tall man has a 6 foot shadow. If a tree is 19.25 feet tall, what is the distance between the tree and the man?
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They are similar triangles. The sides of the triangles will be proportional.
|dw:1384242879300:dw|
Triangles ABC and DEC are similar. AB / BC = DE / EC Substitute and solve for BC.
I got 20.9!
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AB/BC = DE/EC BC = AB/DE * EC = 19.25 / 5.5 * 6.0 = 21 feet
Thank you :) If you don't mind, can you help me out with a different geometry question?
I can try.
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