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Mathematics 24 Online
OpenStudy (anonymous):

Prove tan^3xsec^2x-tan^3x = tan^5x

OpenStudy (anonymous):

\[\tan ^{3}x \times \sec ^{2} x - \tan ^{3}x = \tan ^{5}x \]

hartnn (hartnn):

factor out the tan^3 x from the left side, what do u get on left side then ?

OpenStudy (anonymous):

tan^3 (sec^2x -1)

hartnn (hartnn):

yes, now use the pythagorean identity that sec^2 x = 1+ tan^2 x in that

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