Question

medal for correct answer!!!!!!!!


which set of points can be modeled without a power model?

a) {(2.2, 4.33), (3.5, 6.641), (4.8, 10.184)}
b) {(1.4, 0.133), (2, 0.21), (2.6, 0.333)}
c) {(1.1, 17.155), (1.7, 14.941), (2.3, 13.013)}
d) {(1.4, 5.192), (1.8, 6.104), (2.2, 7.016)}

Answer 1

Examine the slopes
{(1.4, 5.192),(1.8, 6.104),(2.2, 7.016)}
point 1 and point 2:
(6.104-5.192)/(1.8-1.4) = 2.28
(7.016-6.104)/(2.2-1.8) = 2.28
equal slopes
can be modeled without a power model.