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OpenStudy (anonymous):
how to set this up? how many quarts of pure antifreeze must be added to 12 quarts of a 10% antifreeze solution to obtain a 40% antifreeze solution?
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OpenStudy (anonymous):
@Euler271
OpenStudy (anonymous):
0.1(12) + x = 0.4(12 + x)
OpenStudy (anonymous):
x is amount of quarts. since it is pure it is 100% it was 0.1(12) + 1*x = 0.4(12 + x)
OpenStudy (anonymous):
Ok thanks i can do the rest from here
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