Mathematics
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OpenStudy (anonymous):
find k 49x^2-70x+k
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OpenStudy (rsadhvika):
is that the complete q
OpenStudy (anonymous):
yes
OpenStudy (rsadhvika):
may i know from which topic is this from ?
OpenStudy (anonymous):
it just tells me to find k
for 49x^2-70x+k
OpenStudy (anonymous):
from factoring
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OpenStudy (rsadhvika):
its a quadratic and has a constant k,
wat does it mean to find k simply ? there should be some context to it... when it asks
OpenStudy (rsadhvika):
oh ok, i think you need to find k such that the quadratic becomes factorable
OpenStudy (rsadhvika):
revealing some more info about the problem wil help
OpenStudy (anonymous):
hold on let me see..
OpenStudy (rsadhvika):
okay !
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OpenStudy (anonymous):
it says find the integral value pf k that makes 49x^2-70x+k a perfect square trinomial, and express the result in factored form
OpenStudy (anonymous):
@rsadhvika
OpenStudy (rsadhvika):
ohk now that makes sense :)
OpenStudy (rsadhvika):
you need to find k such that you can express
49x^2-70x+k
as
(ax+b)^2
OpenStudy (rsadhvika):
lets try to complete the square,
you familiar wid completing the square ?
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OpenStudy (anonymous):
it's new to me
OpenStudy (rsadhvika):
okay its easy concept lets see
OpenStudy (rsadhvika):
you remember the formula
\(a^2 + 2ab + b^2 = (a+b)^2\)
?
OpenStudy (rsadhvika):
we're going to use that formula
OpenStudy (anonymous):
ok yes
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OpenStudy (rsadhvika):
\(49x^2-70x+k \)
\(7^2x^2-2*30*x+k \)
\((7x)^2-2*30*x+k \)
OpenStudy (rsadhvika):
fine so far ?
OpenStudy (anonymous):
yes
OpenStudy (rsadhvika):
compare it wid the formula above, wats missing ?
OpenStudy (rsadhvika):
\(a^2+2ab + \color{red}{b^2} = (a+b)^2\)
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OpenStudy (rsadhvika):
we dont have \(\color{red}{b^2}\) to complete the square right ?
OpenStudy (rsadhvika):
in place of \(\color{red}{b^2}\) , we just have \(k\)
so to complete the square, \(k = \color{red}{b^2} = 35^2\)
OpenStudy (rsadhvika):
below is the correct equation :-
\((7x)^2-2*35*x+k\)
OpenStudy (rsadhvika):
so if when k = 35^2,
\((7x)^2-2*35*x+35^2 \)
\((7x-35)^2\)
OpenStudy (rsadhvika):
it becomes a perfect square triinomial like above