A gas occupies 200 mL at -73.0°C. To have the same gas occupy 300 mL, should the temperature be increased or decreased?

What is the new temperature in Kelvins? K

Question

A gas occupies 200 mL at -73.0°C. To have the same gas occupy 300 mL, should the temperature be increased or decreased?

What is the new temperature in Kelvins? K

anonymous · Answer

(PV)/T = (PV)/T.  You can exclude the pressures since they are not mentioned.  This means that V1/T1 = V2/T2.  Kelvin is C + 273.  Sooo, solving for T2=(V2T1)/V1.  T2=(0.300L*200K)/0.200L=300K.  NOTE: Volume should be in Liters, Temp in Kelvin, Pressure in atm (not used here).