The length of a rectangle is 2 more than twice the width. Find the dimensions of the rectangle if the perimeter is 76.

If x represents the width of the rectangle, then which expression represents the perimeter?

2x + 2
4x + 4
6x + 4

Question

The length of a rectangle is 2 more than twice the width. Find the dimensions of the rectangle if the perimeter is 76.

If x represents the width of the rectangle, then which expression represents the perimeter?


2x + 2
4x + 4
6x + 4

kainui · Answer

Try to make it into an equation, make the best guess you can and I'll help you fix it up until you get there. Just take it one word at a time. Call things you don't know as variables, like length can be L or Y or whatever. Eventually you should end up with some things that look like an equation.

solomonzelman · Answer

I was answering your question, why did you leave?

solomonzelman · Answer

Continuing from what we left of,

l-2=2w
lw=76

l-2=2w   ---->  l=2w + 2
lw=76

substitute,
w(2w + 2)=76
2w^2+2w-76=0

divide the entire equation by 2
w^2+w-32=0



can you solve this?