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how to find the equation of ax3 + bx2 + cx +d with one point (-2,4)
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You can't -- you'll need at least four.
oh okay it was a test question, and it was the third part maybe that's a problem.
a) Determine an equation for a family of cubic functions with zeros -4, 0, and 2. =x3-2x2-8x b) Write equations for two functions that belong to this family. 1x3+2x2+3x+4 2x3+5x2+3x+1 c) Determine and equation for the member of the family whose graph passes through the point (-2,4). Would any of this help with solving this problem, or is it a lost cause.
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