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Mathematics 16 Online
OpenStudy (math2400):

trig function..eval. w/o calc. I'm confused because it's ⅔...if it was like -½ instead i'd get why it'd be -pi/6...postin

OpenStudy (math2400):

OpenStudy (math2400):

just need the sin part i get the rest

OpenStudy (anonymous):

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OpenStudy (anonymous):

what you need is the third side of the triangle, which you find via pythagoras as \[\sqrt{3^2-2^2}=\sqrt{5}\]

OpenStudy (anonymous):

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OpenStudy (math2400):

ohhh yea! ok got it. I just put one as the other side cuz i remember doing that in class but it was a diff prob. that makes sense. Than you!!

OpenStudy (anonymous):

then you can find all the other trig rations you need, just be careful of what the sign is

OpenStudy (anonymous):

*ratios

OpenStudy (anonymous):

yw

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