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trig function..eval. w/o calc. I'm confused because it's ⅔...if it was like -½ instead i'd get why it'd be -pi/6...postin
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just need the sin part i get the rest
|dw:1384307200689:dw|
what you need is the third side of the triangle, which you find via pythagoras as \[\sqrt{3^2-2^2}=\sqrt{5}\]
|dw:1384307316437:dw|
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ohhh yea! ok got it. I just put one as the other side cuz i remember doing that in class but it was a diff prob. that makes sense. Than you!!
then you can find all the other trig rations you need, just be careful of what the sign is
*ratios
yw
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