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divide 6a^3b^2/9a^5b^4/3a^2b^2
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@MathLegend for my final i got 2a/3a^3b^4 is this right?
Is this a fraction?
yes
sorry it took me long i had to step away fromth e computer for a minute
\[\frac{6a^3b^2}{\frac{9a^5b^4}{3a^2b^2}}\]
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Is that the problem?
yes
Then simplify the denominator first: \[\frac{6a^3b^2}{3a^3b^2}=2\]
2
Yep
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wait it's supposed to be 3a^2b^2 not 3a^3b^2
so i have 2a/3a
is this correct
no
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