Question

Solve 2sin^2(2x)=1

So far I got:
8sin^2(x)cos^2(x)=1

Using sin(2x)

Answer 1

\[2\sin ^{^{2}}2x = 1\]

I got so far: \[8\sin ^{2}x \times \cos ^{2}x = 1\]

Answer 2

Having cos(x) throws me off. ...Do I express cos(x) in terms of sin(x)?