Question

How would I graph the Parabola on a parent graph?
y=(x+3)^2

Answer 1

move the graph to the left 3

Answer 2

Left 3 and up 3?

Answer 3

no just left three

Answer 4

the equation you have is already in vertex form,
y=(x+3)^2 or better said as
y=1(x-(-3))^2 + 0 [do you see how it is still the same equation]

this is now in a similar form to the standard vertex form of
y=a(x-h)^2 + k

where (h,k) are the values of the vertex of the parabola