Question

solve by completing the square.
x^2+2x-7=0

Answer 1

\[(b-\sqrt{b ^{2}-4ac})/2a\]

Answer 2

the coefficients infront of every compomnet of the equation is the a,b,and c

Answer 3

x^2+2x-7=0
add 13 to both sides
x^2+2x-7+13=0+13
x^2+2x+4=13
(x+2)^2=13