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which of the following quartic functions has x=-2 & x=-3 as its only 2 real zeroes? PLEASE HELP ! IVE TRIED & TRIED 1. x^4-5x^3+7x^2-5x+6 2. x^4+5x^3+7x^2+5x+6 3. x^4+5x^3+7x^2-5x-6 4. x^4-5x^3+7x^2+5x-6
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@SolomonZelman
@Lolovitz I did what you said & none of them came out right !
so for x=-2 those functions are equal to 1. 16+40+28+10+6 != 0 2. 16-40+28-10+6=0 3. 16-40+28+10-6!=0 4.16+40+28-10-6!=0 So the only one valid is second So now let's see if number two is valid for x=-2 if it is valid for x=-3 81-135+63-15+6 =0 So those numbers are zero's for f(x) in number two
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