Question

Help Algebra 2.

Answer 1

(a+b)^2=a^2 + 2ab + b^2
a^2 is the x^2
2ab is the 10x -> 2xb = 10x -> b=5
b^5 is the 5^2 = 25
then: (x^2+10x+25)+22 = 0 -> (x+5)^2+22 = 0 -> x+5=+/-sqrt(22)
you have two values: x=+sqrt(22)-5 and x=-sqrt(22)-5

Answer 2

sorry, it's b^2 not b^5

Answer 3

sould you copy and paste it with that correction because its two b^5

Answer 4

let me draw it