Question

solve the following equation by factorisation method

20x^3=5x

Answer 1

20x^3=5x

subtract 5x from both sides

20x^3-5x=0

factor out 5x

5x(4x^2-1)=0

so

5x=0
x=0

and

4x^2-1=0

4x^2=1
x^2=1/4
\[x=\sqrt{1/4}\]

x=1/2, -1/2

Answer 2

thank you!