Find the area : Trapezoid: b(1)= 9 7/8, b(2)= 5 3/4, h= 6 2/3
First, you need the formula for the area of a trapezoid (or you need to figure it out, which is possible but harder to do)
I know the formula hun
do you know the formula for the area of a trapezoid ? http://www.mathgoodies.com/lessons/vol1/area_trapezoid.html it is A= ½ * (b1 + b2) * h replace b1 and b2 with the numbers replace h with the numbers change the mixed numbers to improper fractions add the fractions b1 + b2 (you will need a common denominator... use 4) if you get this far , what do you have ?
* make the common denominator 8 (not 4) add the fractions b1 + b2 (you will need a common denominator)
ive did part of what u said and I now have A= 1/2(79/8 + 23/4) *20/3
looks good so far. you want 23/4 to have a denominator of 8 so that it matches 79/8 multiply BOTH top and bottom by 2 to get 46/8 now you can add the tops
Ok I got that so far
what do you have now ?
I added the numerators and I got 125/8
yes, so the problem is now \[ \frac{1}{2} \frac{125}{8}\frac{20}{3} \] I would simplify first, and then multiply the tops, and multiply the bottoms
Okay thanks ill let u know what I come up with in a sec hun , sorry for the wait I had to discuss somethings with my family
hey hun I cant simplify if I do then what should I do ?
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