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Mathematics 16 Online
OpenStudy (anonymous):

Find the perimeter of the kite below

OpenStudy (anonymous):

OpenStudy (anonymous):

@ranga could you help please?

OpenStudy (ranga):

Take the two right triangles on the left -- the big one and the small one and calculate the hypotenuse for each triangle.

OpenStudy (anonymous):

@ranga I don't calculate the two on the right first?

OpenStudy (ranga):

It is symmetrical. You can calculate either the right or the left but you don't have to calculate both. Add up the hypotenuses on one side and double it to get the perimeter.

OpenStudy (anonymous):

@ranga the perimeter equals 25?

OpenStudy (ranga):

What did you get for the two hypotenuses?

OpenStudy (anonymous):

@ranga 576

OpenStudy (ranga):

No, the individual value of each hypotenuse. The longer hypotenuse = ? The shorter hypotenuse = ?

OpenStudy (anonymous):

@ranga I think I did it completely wrong

OpenStudy (ranga):

try it again.

OpenStudy (anonymous):

@ranga 65?

OpenStudy (ranga):

longer hypotenuse = sqrt( 24^2 + 7^2 ) = sqrt(625) = 25 shorter hypotenuse = sqrt(7^2 + 4^2) = sqrt(49 + 16) = sqrt(65) = 8.06 total = 25 + 8.06 = 33.06. Double it and you get 66.12.

OpenStudy (anonymous):

@ranga thank you!

OpenStudy (ranga):

yw.

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