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OpenStudy (anonymous):
OpenStudy (anonymous):
@ranga could you help please?
OpenStudy (ranga):
Take the two right triangles on the left -- the big one and the small one and calculate the hypotenuse for each triangle.
OpenStudy (anonymous):
@ranga I don't calculate the two on the right first?
OpenStudy (ranga):
It is symmetrical. You can calculate either the right or the left but you don't have to calculate both. Add up the hypotenuses on one side and double it to get the perimeter.
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OpenStudy (anonymous):
@ranga the perimeter equals 25?
OpenStudy (ranga):
What did you get for the two hypotenuses?
OpenStudy (anonymous):
@ranga 576
OpenStudy (ranga):
No, the individual value of each hypotenuse. The longer hypotenuse = ?
The shorter hypotenuse = ?
OpenStudy (anonymous):
@ranga I think I did it completely wrong
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OpenStudy (ranga):
try it again.
OpenStudy (anonymous):
@ranga 65?
OpenStudy (ranga):
longer hypotenuse = sqrt( 24^2 + 7^2 ) = sqrt(625) = 25
shorter hypotenuse = sqrt(7^2 + 4^2) = sqrt(49 + 16) = sqrt(65) = 8.06
total = 25 + 8.06 = 33.06. Double it and you get 66.12.