Question

Please...Need Help in a complicated Question ...Please

Answer 1

Complete the following:
(a) Use the Leading Coefficient Test to determine the graph's end behavior.
(b) Find the x-intercepts. State whether the graph crosses the x-axis or touches the x-axis and turns around at each intercept.
(c) Find the y-intercept.

f(x) = x2(x + 2)

Answer 2

well this video shows how to use the Leading coefficient and f(x)=x^2(x+2)=x^3+2x^2
http://www.youtube.com/watch?v=x24eEnEuj40

Answer 3

http://openstudy.com/study#/updates/5193f339e4b0e9fd532a2ea3

Answer 4

(a)The leading coefficient is positive and thus the graph goes to positive infinity as x-> inf

The x intercepts are the roots, so 0 with multiplicity 2 and -2 with multiplicity 1 thus it touches at 0 and goes through at -2

Answer 5

http://openstudy.com/study#/updates/5193f339e4b0e9fd532a2ea3

Answer 6

a) because the leading coefficient is 1 as x approaches - infinity, y is - infinity and vice versa coming from the positive side
b) make two equations \[x^2 = 0 \] and \[x+2=0\] then solve for x
c) make the equation equal zero then solve like a normal equation