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How many different values can be represented by a 32 bit integer? Reminder: a 32 bit integer is a sequence of 32 bits, and a bit (binary digit) can have 2 values (0 or 1).
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Can someone help me figure this problem?
I do believe that it is 64. Because if all of those 32 numbers are 0 or 1, then there are two possible values that could exist. 2*32=64. I might be wrong though. >.<
alright
Can someone tell me if that answer is right?
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