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Use L'hospital rule lim x^a x->1 ________ x^b
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(additional info) a and b are constants
It is entirely inappropriate to use L'hospital's rule for this limit. It simple is not an indetermiante form away from x = 0. Anywhere x is not zero \(\dfrac{x^{a}}{x^{b}} = x^{a-b}\)
i see. the rule said use the rule where appropriate thanks!
Excellent. I was worried about your course materials. Good reading.
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