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solve using table of signs: x^2-x-6>0
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do you just want to make a table of values?
I don't really understand the question itself which is my problem
Why did you ignore the link @UnkleRhaukus provided to you?
it seemed more complex than what I'm asking, the question I am trying to figure out doesn't have fractions and what not
Yes, but the basics of how to use the table are still the same. You create a chart. At the top you list a row of x values. Along the left side you list the column of factors. Then for each factor you determine whether it will be positive or negative as it approaches the x value of interest: x^2 - x - 6 > 0 factors to (x + 2)(x - 3) |dw:1384409175722:dw|
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