Question

which equation is the equation of a line that passes through (-10, 3) and is perpendicular to y = x - 7 ?

A) y = 5x + 3
B) y = - 1/5x - 7
C) y = - 1/5x + 1
D) y = 1/5x + 5

Answer 1

well unless you meant to put a 5 in front of the x in the original problem none of those works

Answer 2

a 5

Answer 3

ok
so then the slope would flip over and become negative to become -1/5
then you would plug everything into point-slope form (y-y1)=m(x-x1)
y-3=-1/5(x-(-10))
distribute
y-3=-1/5x-2
add three
y=-1/5x+1
the answer is c