Question

One number is 8 less then a second number. Twice the first is 12 more than 4 times the second. Find the numbers.

Value of the first number=?
Value of the second number=?

Answer 1

x = first number
y = second number

y = x - 8
2x = 4y + 12
now we sub x - 8 in for y

2x = 4(x - 8) + 12
2x = 4x - 32 + 12
2x - 4x = -32 + 12
-2x = - 20
x = 10

y = x - 8
y = 10 - 8
y = 2

check..
2x = 4y + 12
2(10) = 4(2) + 12
20 = 8 + 12
20 = 20 (correct)

first number (x) = 10
second number (y) = 2

Answer 2

Thank you!!!