Question

What is the vertex form of the equation?

y = x^2 – 6x + 8

Answer 1

take middle coefficient, divide it by 2, square the result, then both add and subtract that after the middle term

so (-6/2)^2=9

y=x^2-6x+9-9+8

factor the first part, it'll always be a perfect square

y=(x-3)^2-9+8

simplify

y=(x-3)^2-1