A two-player Football game requires that one player select an offensive play and the other chooses a defensive play. -The Offensive player first chooses from 29 different plays. (There are 15 Run plays, 12 Pass plays, and 2 Kick Plays.) -The Defensive Player then chooses one of 18 different plays: (There are 10 cover plays and 8 Blitz plays.) What is the total number of match ups of Offensive and Defensive plays?
Can someone help me out
Offense has 29 different plays Defense has 18 different plays how many combinations are possible? Its important to know that Offense play number 1 with Defense play number 1 is the same as saying Defense play number 1 is Offense play number 1. so, order doesn't mater. Knowing order doesn't mater, would we use combination or the permutation equation?
I figure it out already sorry
combination.
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