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An ellipse has equation x^2/a^2 + y^2/b^2 = 1, A point Q is the intersection of two perpendicular tangents to the ellipse. Given that the equation for a tangent to the ellipse with gradient m is y=mx +- sqrt(a^2m^2 + b^2), show that the locus of Q is a circle.
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\[y=mx \pm \sqrt{a^2m^2+b^2}\]
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