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solve 3csc^2x-4=0
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Add 4 on both sides.
ok
Did you do it?
yes
Now divide by 3 on both sides. You get csc^2 x= something Take square root and you get the answer.
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so csc=2/rt3?
or sin=rt3/2
????
sin(2x) = sqrt(3) / 2 2x = ?
sin(x)=rt3/2*
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2/root 3 is right!!
so x=pi/3 and 2pi/3 correct?
IM SOLVING FOR X ARVINDG
Indeed so sin 60=root 3/2 ie pi/3
Yes well done!
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and 2pi/3?
sin(2x) = sqrt(3) / 2 2x = pi/3 or 2pi/3 x = pi/6 or pi/3 sine is a periodic function and so any multiples of 2pi will also give you the same sine value. x = pi/6 +/- n(2pi) or pi/3 +/- n(2pi) where n = 0, 1, 2, 3, ...
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