What are the solutions of 2x2 + 3x= –8?

Question

anonymous · Answer

first, you need to transpose -8 to the left side or in other words, make the right side zero.

you will end up with a quadratic equation,
use the quadratic formula to find the roots/ solutions/factors of the equation$$x=\left( \frac{ -b \pm \sqrt{b^2-4ac} }{ 2a} \right)$$

anonymous · Answer

how would u make it equal zero? @Data_LG2

anonymous · Answer

you need to transpose -8 to the left side so it will be $2x^2+3x +8=0$
then a=2, b=3, c=8

anonymous · Answer

√3^2−4(2)(8)
---------------------------
         2 * 2

is that right

anonymous · Answer

you forgot something

anonymous · Answer

what did i forget

anonymous · Answer

$$"-b \pm "$$ before the discriminant

anonymous · Answer

-3+- √3^2−4(2)(8)
---------------------------
         2 * 2