Question

What are the solutions of 2x2 + 3x= –8?

Answer 1

first, you need to transpose -8 to the left side or in other words, make the right side zero.

you will end up with a quadratic equation,
use the quadratic formula to find the roots/ solutions/factors of the equation\[x=\left( \frac{ -b \pm \sqrt{b^2-4ac} }{ 2a} \right)\]

Answer 2

how would u make it equal zero? @Data_LG2

Answer 3

you need to transpose -8 to the left side so it will be \(2x^2+3x +8=0\)
then a=2, b=3, c=8

Answer 4

√3^2−4(2)(8)
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2 * 2

is that right

Answer 5

you forgot something

Answer 6

what did i forget

Answer 7

\["-b \pm "\] before the discriminant

Answer 8

-3+- √3^2−4(2)(8)
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2 * 2