An object has been thrown straight up into the air. The formula
h = vt − 16t2
gives the height h of the object above the ground after t seconds, when it is thrown upward with an initial velocity v. An object has been thrown straight up into the air. The formula
h = vt − 16t2
gives the height h of the object above the ground after t seconds, when it is thrown upward with an initial velocity v.

After how many seconds will the object hit the ground if it is thrown with a velocity of 224 feet per second?
t = . sec

Question

An object has been thrown straight up into the air. The formula 
h = vt − 16t2
 gives the height h of the object above the ground after t seconds, when it is thrown upward with an initial velocity v. An object has been thrown straight up into the air. The formula 
h = vt − 16t2
 gives the height h of the object above the ground after t seconds, when it is thrown upward with an initial velocity v.
 
After how many seconds will the object hit the ground if it is thrown with a velocity of 224 feet per second?
 t = . sec

anonymous · Answer

Since v = 224 the equation for h is$$h=224t-16t ^{2}$$When you throw a object straight into the air, there are two times where the object is at the ground; 1 from when you threw and 2 after the object has been thrown.|dw:1384490970418:dw|Now set the equation equal to zero. This is how you find the t, so set h (height equal to zero)$$0=224t-16t ^{2}$$Factor to find the t.