James added 3 and two-thirds plus 4 and one-eighth. His work is shown here. What did James do right? What did he do wrong? What should he have done? three and two-thirds plus 4 and one-eighth equals 7 and three-elevenths
@Chineseboy15
@angel12310 please come help me
yes
\[3\frac{ 2 }{ 3 }+4\frac{ 1 }{ 8 }\] First make the fractions have a common denominator. \[3\frac{ 2 }{ 3 }+4\frac{ 1 }{ 8 }\] \[ =\frac{ 11 }{ 3 }+\frac{ 33 }{ 8 }\] \[=\frac{ 11\times8 }{ 3\times8 }+\frac{ 33\times3 }{ 8\times3 }\] \[=\frac{ 88 }{ 24 }+\frac{ 99 }{ 24 }\] \[=\frac{ 187 }{ 24 }\] \[=7\frac{ 19 }{ 24 }\] James do wrong.
I hope my reply does not come so late. It take me a long time.
3 2/3 + 4 1/8 11/3 + 33/8 = ((11 × 8) + (33 × 3)) / (3 × 8) = (88 + 99) / 24 = 187/24 = 187/24 = 7 19/24
it is ok, I understand :)
wow! hold on a sec I gotta read this!
whatever Bye
Can you understand?
no, I dont
can u explain it to me?
\[3\frac{ 2 }{ 3 }=\frac{ 11 }{ 3 }, 4\frac{ 1 }{ 8 }=\frac{ 33 }{ 8 }\], is it?
hmm...
3 2/3 + 4 1/8 then change them into an improper fraction: 11/3 + 33/8 = ((11 × 8) + (33 × 3)) / (3 × 8) = (88 + 99) / 24 = 187/24 = 187/24 = 7 19/24
angel, can u in words?
ok so the answer is?
Well, if we want to add them together, we need to make two fractions have same denominators.
I has to write it you know
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