Question

WILL GIVE MEDALS find all zeros of the equation -3x^4+27x^2+1200=0

Answer 1

@hartnn pls help

Answer 2

\[-3(x^4 - 9x^2 - 400) = 0\]
\[-3(x^2 - 25)(x^2 + 16) = 0\]

Set each factor equal to zero.

\[x^2 - 25 = 0\]
\[x = 5, -5\]

\[x^2 + 16 = 0\]
\[x = 4i, -4i\]

Leave -3 out because when you set =3 equal to zero: -3 = 0
they are NOT equal to zero!!!!!

But when you simplify, you should write it out as:
\[-3(x^2 + 16)(x-5)(x+5) = 0\]

Answer 3

got that ? still need any help ?

Answer 4

nope im good, thanks skiller!

Answer 5

Glad I could assist you :)