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A 1.10-kg wrench is acting on a nut trying to turn it. The length of the wrench lies directly to the east of the nut. A force 150.0 N acts on the wrench at a position 15.0 cm from the center of the nut in a direction 30.0° north of east. What is the magnitude of the torque about the center of the nut?
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150N*sin30*.15 =11.25NM. most of these problems are going to be trig formatted. use SOHCAHTOA and quotient identities if need be. Use the triangle method for visualization, draw the right triangle with the properties given.
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