Question

. Solve using perfect square factoring patterns. y2 + 14y + 49 = 0
{–7}
{0, –1}
{7}
{7, –7}

Answer 1

why is y^2 + 14y + 49 a perfect square trinomial?

Answer 2

The factoring pattern you are trying to match is $$\huge a^2+2ab+b^2$$

Answer 3

perfect square factoring patterns looks like this:
a^2 + 2ab + b^2 = (a+b)^2

you have:
y2 + 14y + 49

do you see how the places of each term are like the perfect square places?

Answer 4

$$\huge a^2+2ab+b^2=(a+b)^2$$ $$\huge y^2 + 14y + 49$$ $$\huge y^2 + 2(7)y + 7^2=(?+?)^2$$