Question

solve triangle ABC given that A=56 degrees, B=57 degrees and b=9
a. C=64 degrees, a=10.2, c=9.8
b. C=67 degrees, a= 10.2, c=9.88
c. C=67 degrees, a=8.9, c=9.88
d. C=66 degrees, a=8.7, c=9.88

Answer 1

well you can find C by angle sum of a triangle...

then find the sides using the law of sines

\[\frac{b}{\sin(B)} = \frac{a}{\sin(A)} = \frac{c}{\sin(C)}\]

hope this helps.