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Mathematics 11 Online
OpenStudy (anonymous):

How much pure antifreeze must be added to 30 L of a solution that is 45% antifreeze to make a solution that is 60% antifreeze?

hero (hero):

x = pure antifreeze y = total solution Total Liters of Solution x + 30 = y Total Percent Antifreeze in Solution 1(x) + .45(30) = .60(y) By the way, 1 is equivalent to 100% Solve the following system x + 30 = y x + .45(30) = .60y

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