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everything looks really good...except #74 error should be y = (x-1)^2 -10
Okay and how would I do this: y= 3x^2 - 12x + 1
^do what? complete the square...? first factor out the 3 \[\large y= 3x^2 - 12x + 1\] \[\large y= 3(x^2 - 4x) + 1\]
then divide by 3?
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No, complete the square from there
how would I do that @agent0smith
The same way you did all those other questions (it seems like you know how to complete the square already). You just have to not forget about the 3.
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